If plane passes through the point (1, 1,1) and is perpendicular to the line,`(x-1)/3=(y-1)/0=(z-1)/4`, then its perpendicular distance from the origin is

A plane passes through the point (1,1,1) and is perpendicular to the line (x-2)/(3) = (z+5)/(4) = (y-1)/0 . The perpendicular distance from the origin to the plane is

A plane passes through (1,1,1). It is perpendicular to the line (x-1)/(3)= (y-1)/(0) - (z-1)/(4) Then the distance of this plane from the origin is............

Find the equation plane passing through the point (2,3,1 )and perpendicular to the line (x-1)/1=(y-2)/-2=(z+1)/3

The equation of a plane through the point A(1,0,-1) and perpendicular to the line (x+1)/2=(y+3)/4=(z+7)/-3 is

A plane passes through (2, 3, -1) and is perpendicular to the line having direction ratios 3, -4,7. The perpendicular distance from the origin to this plane is

Write the equation of the plane passing through the point (2, 3, 1) and perpendicular to the line. (x-1)/1=(y-2)/-1=(z+1)/3

Find the equations of the plane passing through the point (2, 1, 3) and perpendicular to the lines (x-1)/1=(y-2)/2=(z-3)/3 .