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l isum(n-gtoo)sum(r=1)^n1/(sqrt(4n^2-r^2...

`l isum_(n-gtoo)sum_(r=1)^n1/(sqrt(4n^2-r^2))`

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Lt_(ntooo)sum_(r=1)^(n)(1)/(sqrt(4n^(2)-r^(2)))=

Lt_(ntooo)sum_(r=1)^(n-1)(1)/(sqrt(n^(2)-r^(2)))=

Lt_(n rarr oo) sum_(r=1)^(n)[(1)/(sqrt(4n^(2) - r^(2)))]

The value of lim_(n to oo)sum_(r=1)^(n)(1)/(n) sqrt(((n+r)/(n-r))) is :

The value of lim_(n to oo)sum_(r=1)^(n)(1)/(n) sqrt(((n+r)/(n-r))) is :

Find Lt(n rarr oo) sum_(r=0)^(n-1)(1)/(sqrt(n^(2) - r^(2))

Evaluate S=sum_(r=0)^(n-1)(1)/(sqrt(4n^(2)-r^(2)))as n rarrinfty .

Evaluate S=sum_(r=0)^(n-1)(1)/(sqrt(4n^(2)-r^(2)))as n rarrinfty .

lim_(n rarr oo) sum_(r=0)^(n-1) 1/(sqrt(n^(2)-r^(2))) =