`y^(3)-y^(2)+ya+y-a-1`

Factorise y ^(3) + y ^(2) -y -1

((y^(3)-3y^(2)+5y-1)/(y-1))

Simplify: (y^3-2y^2+3y-4) (y-1) - (24-3)(y^2-y+1)

If p(y)=y^(3)+y^(2)+y+1 find : (i) y(1) (ii) y(-1)

If p(y)=y^(3)+y^(2)+y+1 find : (i) y(1) (ii) y(-1)

Find the value of (x+y) ,if (x+(y^(3))/(x^(2)))^(-1)-((x^(2))/(y)+(y^(2))/(x))^(-1)+((x^(3))/(y^(2))+y)^(-1)=(1)/(3)

"Find the value of "(x+y)," if "(x+(y^(3))/(x^(2)))^(-1)-((x^(2))/(y)+(y^(2))/(x))^(-1)+((x^(3))/(y^(2))+y)^(-1)=(1)/(3)

x^(3)-y^(3)+3y^(2)-3y+1

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

Form differential equation for y=cx-2c+c^(3) A) y=xy_(1)-2y_(1)+(y_(1))^(3) B) y=xy_(1) C) yy_(1)+x+y_(1) D) y_(3)-2y_(2)+xy_(1)=y