`20 mol` of `M//10 CH_(3)COOH` solution is titrated with `M//10 NaOH` solution. After addition of `16 mL` solution of `NaOH`. What is the `pH` of the solution `(pK_(a) = 4.74)`

The pH of 10^(-3) M solution of NaOH is

Calculate the pH of the solutions when following conditions are provided: a. 20mL of M//10 CH_(3)COOH solution is titrated with M//10 solution of NaOH . i. No titration is carried out. ii. When 10mL of NaOH is added. iii. When 20mL of NaOH is added. iv. When 30mL of NaOH is added. (pK_(a) of CH_(3) COOH = 4.74) b. 20mL of M//10 NaOH solutions sio titrated with M//10 solution of CH_(3)COOH . i. No titration is carried out. ii. When 18mL of Ch_(3)COOH is added. iii. When 20mL of CH_(3)COOH is added. iv. When 40mL of CH_(3)COOH is added. c. 10mL of M//10 NH_(4)OH solution is titrated with M//10 solution of H_(2)SO_(4) . i. No titration is carried out. ii. When 4mL of H_(2)SO_(4) is added. iii. When 5mL of H_(2)SO_(4) is added. iv. When 10mL of H_(2)So_(4) is added. pK_(a) of NH_(4)OH = 4.76 d. 10mL of M//10H_(2)SO_(4) solution is titrated with M//10 solution of NH_(4)OH . i. No titration is carried out. ii. When 10mL of NH_(4)OH is added. iii. When 20mL of NH_(4)OH is added. When 40mL of NH_(4)OH is added.

pH of 10^-4(M) NaOH Solution—

Calculate the pH of the solutions when following conditions are provided: a. 20mL of M//10 CH_(3)COOH solution is titrated with M//10 solution of NaOH . i. No titration is carried out. (pK_(a) of CH_(3) COOH = 4.74)

100 ml of 0.2 M CH_3COOH is titrated with 0.2 M NaOH solution. The pH of of the solution at equivalent point will be ( pKa of CH_3COOH=4.76 )

50 ml 0.1 N CH_3COOH solution is mixed with 25 ml 0.1 N NaOH solution. What is the pH of the final solution? Given : pK_a of CH_3COOH = 4.74

If 50 ml 0.2 (M) CH_3COOH is mixed with 20 ml 0.2 (M) NaOH solution, then what will be the pH of the mixed solution?

100 ml of 0.2 M CH3COOH is titrated with 0.2 M NaOH solution. The pH of of the solution at equivalent point will be (pKa of CH3COOH=4.76)