The voltmeter V in the figure. Reads `117V` and the ammeter A reads `0*13A`. The resistance of the voltmeter is `9000Omega` and the resistance of ammeter is `0*015Omega`. Compute (i) the resistance R, (ii) the power input to R.

If the voltmeter reads 0.2 V and the ammeter reads 0.101A, the resistance of the voltmeter is (in ohm)

If resistance of voltmeter is 10000 Omega and resistance of ammeter is 2Omega then find R when voltmeter reads 12 V and ammeter reads 0.1 A

The voltmeter reads 40 V across 60 Omega resistance. The resistance of voltmeter is. .

The ammeter A reads 2A and the voltmeter V reads 20V, the value of resistance R is (Assuming finite resistance's of ammeter and voltmeter)

The ammeter A reads 2A and the voltmeter V reads 20V, the value of resistance R is (Assuming finite resistance's of ammeter and voltmeter)

The ammeter A reads 2A and the voltmeter V reads 20V, the value of resistance R is (Assuming finite resistance's of ammeter and voltmeter)

Resistance value of an unknown resistor is calculated using the formula R=V/I where V and I be the readings of the voltmeter and the ammeter respectively. Consider the circuits below. The internal resistances of the voltmeter and the ammeter ( R_v and R_G respectively ) are finite and non zero. Let R_v and R_G be the calculated values in the two cases A and B respectively. If the resistance of voltmeter is R_v=1kOmega and that of ammeter is R_G=1Omega the magnitude of the percentage error in the measurement of R (the value of R is nearly 10Omega ) is:

The voltmeter connected in the circuit shows a reading of 5 V. Resistance of the voltmeter (in Omega ) is

The power dissipated in resistor R_(3) shown in the figure is 15 W. The reading the ammeter is 500 mA and the reading of the voltmeter is 10 V. Ammeter, voltmeter and battery are ideal. Find the resistance R_(3)