निम्नांकित में सही मान कोष्ठक से चुने -
`sec0^(@). " "[0, 2, 1, (1)/(0)]`

cos(10^0)dot(cos 20^0)dotcos(40^0)= " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " 1. 1/8cot10^0 2. (1)/8t a n 10^0 3. 1/4sec(10^0) 4. 1/4cos e c(10^0)

cos(10^0)dot(cos 20^0)dotcos(40^0)= " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " " 1. 1/8cot10^0 2. (1)/8t a n 10^0 3. 1/4sec(10^0) 4. 1/4cos e c(10^0)

sec ^ (2) 12 ^ (0) - (1) / (tan ^ (2) 78 ^ (@))

If 6 sec^(2)theta - 5 sec theta + 1 = 0 then theta =