If n is odd, p is even, and q is odd, what is `n+p+q`?

Suppose p is even and q is odd. Then which of the following CANNOT be an integer?

For every a, b in N a" @ "b=a^(2)" when "(a+b)" is even" =a^(2)-b^(2)" when "(a+b)" is odd" a#b=b^(2)" when "axxb" is odd" =a^(2)-b^(2)" when "axxb" is even" Find the value of (p#q)-(q" @ "p)-(q" @ "p),p is even and q is odd :

If m , n , o, p a n d q are integers, then m (n +o) (p-q) must be even when which of the following is even? m (b) p (c) m + n (d) n + p

p : x is odd , q is x^(2) is odd. The symbolic form of " x is odd and x^(2) is not odd", is

In the expansion of (x+a)^n if the sum of odd terms is P and the sum of even terms is Q , then

p : x is odd , q : x^(2) is odd, the symbolic form of "x is even or x^(2) is odd", is

In the expansion of (x+a)^n if the sum of odd terms is P and the sum of even terms is Q , then a. P^2-Q^2=(x^2-a^2)^n b. 4P Q=(x+a)^(2n)-(x-a)^(2n) c. 2(P^2+Q^2)=(x+a)^(2n)+(x-a)^(2n) d. none of these