Home
Class 12
MATHS
If the pdf of a curve X is f(x)={{:(3(...

If the pdf of a curve X is
`f(x)={{:(3(1-2x^2)","0ltxlt1),(0","xle0" or "xge1):}`
Then, the cdf of X is equal to

Promotional Banner

Similar Questions

Explore conceptually related problems

The pdf of a curve X is f(x)={{:(k/sqrtx","0ltxlt4),(0","xle0" or "xge4):} Then , P(Xge1) is equal to

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f(x)={{:(kx^(2)(1-x)","0ltxlt1),(0", otherwise"):} , then k =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then k =

If the pdf of a curve X is f(x)={{:(x/8,0ltxlt4),(0,"elsewhere"):} Then P(Xlt1) and P(Xge2) are

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then c.d.f. of X is

The p.d.f. of a r.v. X is f_(X)(x)={{:((k)/(sqrt(x))","0ltxlt4),(0", otherwise"):} , then c.d.f. of X is:

The p.d.f. of a r.v. X is f(x)={{:(0.5x","0ltxlt2),(0", otherwise"):} , then P(X le1) =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then P(Xlt(1)/(2)) =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then P((1)/(4)ltxlt(1)/(3)) =