The displacement of a particle is given by `y=(6t^2+3t+4)m`, where t is in seconds. Calculate the instantaneous speed of the particle.

The displacement of a particle is given by x = (t-2)^(2) where x is in metre and t in second. The distance covered by the particle in first 4 seconds is

The displacement of a particle is given by x = (t-2)^2 where x is in metres and t in seconds. The distance covered by the particle in first 4 seconds is

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

The displacement of a particle is moving by x = (t - 2)^2 where x is in metres and t in second. The distance covered by the particle in first 4 seconds is.

Chose the correct option The displacement s of a particle is expressed by the relation s=(6t^2 - 3t + 6) metres and t is in seconds. The velocity of the particle at t = 2 seconds is ... m//s .

The angular displacement of a particle is given by theta = t^3 + 2t +1 , where t is time in seconds. Its angular acceleration at t=2s is