((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=i

Find the real values of x and y,quad if :((1+i)x-2i)/(3+i)+((2-3i)y+i)/(3-i)=

The values of x and y which satisfy the equation ((1+i) x-2 i)/(3+i)+((2-3 i) y+i)/(3-i)=i are

Solve ((1-i)x+3i)/(2+i)+((3+2i)y+i)/(2-i)=-i "where" x, y, in R.

" If "z=((1+i)(1+2i)(1+3i))/((1-i)(2-i)(3-i))" then the principal argument of "z"

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Write the following in the form x+iy: (i) (2i)^(3) (ii) i^(-35) (iii) (-i)(2i)(-(1)/(8)i)^(3) .

Express the result in the form x+iy, where x,y are real number i=sqrt(-1) : (i) (2-3i)/(4-i) (ii) (2+3i)/(-5-4i) (iii) (1+i)/(3+i) (iv) (3+2i)/(4-3i)