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Evaluate : int (0)^(pi//4) sin 2x sin 3 ...

Evaluate : `int _(0)^(pi//4) sin 2x sin 3 x dx`

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`int_(0)^(pi//4) sin 2x sin 3x dx `
`=1/2 int_(0)^(pi//4) (2sin 3x sin 2x) dx`
`=1/2 int_(0)^(pi//4) (cos x - cos 5x ) dx`
` =1/2 [sin x -(1)/(5) sin 5x ]_(0)^(pi//4)`
`=1/2[(sin.(pi)/(4)-(1)/(5) sin .(5pi)/(4)) -(sin 0-(1)/(5) sin0)]`
` =1/2[((1)/(sqrt(2))+(1)/(5sqrt(2)))-0 ]=(3)/(5sqrt(2)).`
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