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int cosec^(2)x. sqrt(cot) dx...

`int cosec^(2)x. sqrt(cot) dx`

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To solve the integral \( \int \csc^2 x \sqrt{\cot x} \, dx \), we can follow these steps: ### Step 1: Substitution Let \( t = \cot x \). Then, we differentiate \( t \) with respect to \( x \): \[ \frac{dt}{dx} = -\csc^2 x \implies dt = -\csc^2 x \, dx \implies dx = -\frac{dt}{\csc^2 x} \] ### Step 2: Rewrite the Integral Substituting \( t \) and \( dx \) into the integral, we have: \[ \int \csc^2 x \sqrt{\cot x} \, dx = \int \csc^2 x \sqrt{t} \left(-\frac{dt}{\csc^2 x}\right) \] This simplifies to: \[ -\int \sqrt{t} \, dt \] ### Step 3: Integrate Now we can integrate \( -\int \sqrt{t} \, dt \): \[ -\int t^{1/2} \, dt = -\left(\frac{t^{3/2}}{3/2}\right) + C = -\frac{2}{3} t^{3/2} + C \] ### Step 4: Substitute Back Now, we substitute back \( t = \cot x \): \[ -\frac{2}{3} (\cot x)^{3/2} + C \] ### Final Answer Thus, the integral \( \int \csc^2 x \sqrt{\cot x} \, dx \) is: \[ -\frac{2}{3} \cot^{3/2} x + C \] ---
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Knowledge Check

  • int cosecx(cosec x + cot x) dx = ?

    A
    `cot x - cosec x + C`
    B
    `-cot x + cosec x + C`
    C
    `cotx + cosec x + C`
    D
    `-cot x - cosec + C`
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