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sin 4x sin 8x...

`sin 4x sin 8x`

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To solve the integral of \( \sin(4x) \sin(8x) \), we can use a trigonometric identity to simplify the expression. The identity we will use is: \[ \sin A \sin B = \frac{1}{2} [\cos(A - B) - \cos(A + B)] \] ### Step-by-Step Solution: ...
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