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int(0)^(pi/2) cos 2x dx...

`int_(0)^(pi/2) cos 2x dx`

Text Solution

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`int_(0)^(pi//2) cos 2x dx=[(sin 2x)/(2)]_(0)^(pi//2)`
`=(1)/(2)[sin 2x]_(0)^(pi//2)`
`=(1)/(2) [(sin 2xx .(pi)/(2))-sin(0)] =(1)/(2) (0-0)=0`
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