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Find the value of int0^1x(1-x)^ndx...

Find the value of `int_0^1x(1-x)^ndx`

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`int_(0)^(1)x(1-x)^(n)dx`
`=int_(0)^(1)(1-x).{1-(1-x)}^(n)dx`
`=int_(0)^(1)(1-x).x^(n)dx`
`=int_(0)^(1)(x^(n)-x^(n+1))dx`
`=[(x^(n+1))/(n+1)-(x^(n+2))/(n+2)]_(0)^(1)`
`=(1)/(n+1)-(1)/(n+2)=(1)/((n+1)(n+2))`
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