In the given circuit , the two cells have no internal resistance. Calculate the potential difference across the `20 Omega` resistor .

100 J of heat are produced each second in a 4 Omega resistance. Find the potential difference across the resistor.

In the given circuit, the current through 2 Omega resistor is

When the terminals of a cells are connected by a wire of resistance 4 Omega , the potential difference across the cell is 1.6 V . If a wire of the same resistance is connected in parallel with the first, the potential difference becomes 1 . 33 v . The emf and internal resistance of the cell are respectively

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is

A cell of emf E having an internal resistance r is connected to an external resistance R. The potential difference V across the resistance R varies with R as shown in figure by the curve: R

4muF capacitor and a resistance 2.5M Omega are in series with 12V battery, Find the time after which the potential difference across the capacitor is 3 times the potential difference across the resistor. [Given In ( 2 ) = 0.693]