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Let alpha be the distance between lines ...

Let `alpha` be the distance between lines `-x+y=2` and `x-y=2` and `beta` be the distance between the lines `4x-3y= 5` and `6y-8x = 1`, then

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Let alpha be the distance between the lines x-y+2=0 and x-y =2 and beta be the distance between the lines 4x - 3y =5 and 6y-8x=1, then the value of (alpha)/(beta) is-

Let alpha be the distance between lines -x+y=2 and x-y=2 beta be the distance between the lines 4x-3y=5 and 6y-8x=1, then

The distance between the lines 4x+3y=11 and 8x+6y=15 is

The distance between the lines 4x + 3y = 11 and 8x+6y=15 is

The distance between the lines 4x + 3y = 11 and 8x + 6y = 15 is

(a)Find the distance between the lines 4x+3y=11 and 8x+6y=15 .

The distance between the lines 4x + 3y = 11 and 8x + 6y = 15 is