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[CH(2)=CH(2)(g)+H(2)(g)rarr CH(3)-CH(3)(...

[CH_(2)=CH_(2)(g)+H_(2)(g)rarr CH_(3)-CH_(3)(g)" .The heat of reaction is (bond energy of "C-C=80kcal,],[C=C=145kcal,C-H=98kcal,H-H=103kcal]

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CH_(2)=CH_(2)(g)+H_(2)(g) to CH_(3) to CH_(3)(g) The heat of reaction is [bond energy of C=C=80 kcal, C=C=145 kcal, C-H=98 kcal, H-H=103 kcal]

Calculate the heat of the reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3)CH_(3)(g) given that bond energy of C-C, C=C, C-H and H-H is 80, 145, 98 and 103 kcal.

Calculate the enthalpy of the following reaction: H_(2)C =CH_(2)(g) +H_(2)(g) rarr CH_(3)-CH_(3)(g) The bond energies of C-H, C-C,C=C , and H-H are 99,83,147 ,and 104kcal respectively.

Calculate the enthalpy of the following reaction: H_(2)C =CH_(2)(g) +H_(2)(g) rarr CH_(3)-CH_(3)(g) The bond enegries of C-H, C-C,C=C , and H-H are 99,83,147 ,and 104kcal respectively.

Calculate enthalpy change of the following reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g) The bond energy of C - H, C - C, C = C, H - H are 414,347, 615 and 436 kJ mol^(-1) respectively.

Calculate enthalpy change of the following reaction : CH_(2) = CH_(2)(g) + H_(2)(g) rarr CH_(3) - CH_(3)(g) The bond energy of C - H, C - C, C = C, H - H are 414, 615 and 436 kJ mol^(-1) respectively.

Calculate enthalpy change of the following reaction : H_(2)C=CH_(2(g))+H_(2(g)) rarr H_(3)C-CH_(3(g)) The bond energy of C-H,C-C,C=C,H-H are 414,347,615 and 435k J mol^(-1) respectively.

Calculate the enthalpy change for the reaction CH_2 = CH_2(g) + H_2(g0 to CH_3 - CH_3(g) . The bond energies of C - C , C - H, H- H and C = C bonds are 83 kcal, 99 kcal 104 kcal and 145 kcal respectivley.