" Interval "[0,9]" Polynomial in "x^(3)-18x^(2)+96x" Find the minimum and highest values of. "

The polynomial x^(3)-2x^(2)-9x+18 is equivalent to

If (-2) is the zero of polynomial 9x^(3)+18x^(2)-x-2 find the remaining zeros.

The smallest value of the polynomial x^(3)-18x^(2)+96x is [0,9] is

The smallest value of th polynomial x^(3) - 18 x^(2) + 96 x in [0,9] is

f(x)=2x^(3)-18x^(2)+30x+36 has minimum value at x = ….

If the polynomial (x^(3)-3x^(2)+ax+18) is divided by (x-4), the remainder is 58. Find the value of a.

Find minimum value of (9-x) (2-x)

The smallest value of the polynomial x^(3)-18x^(2)+96x in [0, 9] is …………..

Solve the following questions : If the value of the polynomial x^3 + 3x + a for x = 2 is 9 , then find the value of a .