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If 3sinx+4cosx=5, then 6(tan)x/2-9(sin)^...

If `3sinx+4cosx=5,` then `6(tan)x/2-9(sin)^2x/2=`

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3sinx+4cosx=5implies6tan""(x)/(2)-9tan^(2)""(x)/(2) =

3 sin x+ 4 cos x= 5implies 6 tan""(x)/(2)-9 tan^(2)""(x)/(2)=