A straight line segment (3, 4) in the first quadrant meets the co ordinate axes in A and B. The minimum area of `Delta AOB` is

A straight line through the point (3,4) in the first quadrant meets the axes at A and B . The minimum area of the triangle OAB is

A straight line with negative slope passing the point (1, 4) meets the coordinate axes at A and B. The minimum value of OA + OB =

A straight line passes through the points P(-1, 4) and Q(5,-2). It intersects the co-ordinate axes at points A and B. M is the midpoint of the segment AB. Find : The co-ordinates of A and B.

A straight line passes through the points P(-1, 4) and Q(5,-2). It intersects the co-ordinate axes at points A and B. M is the midpoint of the segment AB. Find : The co-ordinates of M.

A straight line through the fixed point (3,4) cuts the coordinate axes at A and B. If the area of the triangle formed by the line and the coordinate axes is least then the the ratio of intercepts is …….. And the min area is ……..

A straight line passes through the points P(-1, 4) and Q(5,-2). It intersects the co-ordinate axes at points A and B. M is the midpoint of the segment AB. Find : The equation of the line.

The equation of the circle in the first quadrant which touch the co-ordinate axes and the line 3x+4y=12 is

If a straight line I passing through P(3,4) meets positive co-ordinate axes at A &B such that area of triangle OAB is minimum (where O is origin) then slope of I is

The plane lx+my+nz=p intersects co-ordinate axes at A,B and C .If area of Delta ABC is Delta ,then

A straight line passing through P(3,1) meets the coordinate axes at Aa n dB . It is given that the distance of this straight line from the origin O is maximum. The area of triangle O A B is equal to