`y=log x` is a solution of the D.E.

y = log x + c is a solution of the differential equation x(d^(2)y)/(dx^(2)) + (dy)/(dx) = 0

If y = y (x) is the solution of the differential equation (5 + e^(x))/(2 + y) * (dy)/(dx) + e^(x) = 0 satisfying y(0) = 1 , then a value of y (log _(e) 13) is :

IF y = y (x) is the solution of the differential equation, x (dy)/(dx) = y (log_(e) y - log_(e) x + 1) , when y(1) = 2, then y(2) is equal to _______

IF y' = y/x(log y - log x+1), then the solution of the equation is :

IF y' = y/x(log y - log x+1), then the solution of the equation is :

Let y = y (x) be the solution of the differential equation dy = e^(alpha . x + y) dx , alpha in N . If y ( log_(e) 2) = log _(e) 2 and y(0) = log _(e) ((1)/(2)) , then the value of alpha is equal to _____

Let y=y(x) be the solution of the differential equation,x((dy)/(dx))+y=x log_(e)x,(x>1) if 2y(2)=log_(e)4-1, then y(e) is equal to: (a)-((e)/(2))(b)-((e^(2))/(2))(c)(e)/(4)(d)(e^(2))/(4)

If x(dy)/(dx)=y(log_(e)y-log_(e)x+1) ,then solution of the equation is

General solution of the D.E. y_(2)=e^(-2x) is y=