Calculate the equivalent capacitance between two points A and B in the following figure:

Explanation

Here capacitors, `C_(1),C_(2) and C_(3)` are connected in parallel.
i.e., `C.=C_(1)+C_(2)+C_(3)`
or `C.=2+3+5`
or `C.=10muF`

Now. and `C_(4)(10muF)` are in series.
`therefore` Equivalent capacitance of the combination between A and B is
`C=(C.xx10)/(C.+10)=(10xx10)/(10+10)=(100)/(20)=5muF`.