Find the final charge on each capacitor if they are connected as shown in the figure.

Explanation

Let us find the resultant of two capacitors `C_(2) and C_(3)` in parallel to each other. It is `C_(p)=6+6=12muF`. Now capacitors `C_(1),C_p and C_(4)`, each of `12muF` are in series.

`therefore (1)/(C_(s))=(1)/(C_(1))+(1)/(C_(p))+(1)/(C_(4))`
`=(1)/(12)+(1)/(12)+(1)/(12)`
or `(1)/(C_(s))=(3)/(12) or C_(s)=4muF`.
`therefore` Resultant capacitance between A and B is `4muF`.