What is the charge on a metal when 5 electrons are removed from it?

Options

A. `8.0xx10^(-19)C`
B. `16xx10^(-19)C`
C. `1.6xx10^(-19)C`
D. 0

Answer

To determine the charge on a metal when 5 electrons are removed from it, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the charge of a single electron**:
The charge of one electron is approximately \( -1.6 \times 10^{-19} \) coulombs. This is a fundamental constant in electrostatics.

2. **Calculate the total charge of the removed electrons**:
Since we are removing 5 electrons, we need to calculate the total charge removed. The formula for the total charge (Q) when removing multiple electrons is:
\[ Q = n \times e \]
where \( n \) is the number of electrons removed and \( e \) is the charge of one electron.
Here, \( n = 5 \) and \( e = -1.6 \times 10^{-19} \) coulombs.

3. **Substitute the values into the formula**:
\[ Q = 5 \times (-1.6 \times 10^{-19}) = -8.0 \times 10^{-19} \text{ coulombs} \]

4. **Determine the charge on the metal after removing the electrons**:
When electrons are removed from a neutral metal, the metal becomes positively charged. Therefore, the charge on the metal after removing 5 electrons will be:
\[ \text{Charge on metal} = +8.0 \times 10^{-19} \text{ coulombs} \]

### Final Answer:
The charge on the metal when 5 electrons are removed from it is \( +8.0 \times 10^{-19} \) coulombs.

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