If the frequency of incident radiation on a photocell is doubled for the same intensity, then what change will you observe in photoelectric current ?

Explanation

To solve the problem, we need to analyze the relationship between the frequency of incident radiation, the intensity of the radiation, and the photoelectric current in a photocell.

### Step-by-Step Solution:

1. **Understanding Photoelectric Effect**: The photoelectric effect states that when light of a certain frequency (or higher) strikes a material, it can eject electrons from that material. The number of electrons ejected (and thus the photoelectric current) depends on the intensity of the light and not directly on the frequency.

2. **Frequency and Intensity Relationship**: The intensity of the radiation is related to the number of photons striking the surface per unit time. If the frequency is doubled while keeping the intensity constant, the energy of each photon increases (since energy of a photon, E = hf, where h is Planck's constant and f is the frequency).

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