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The maximum kinetic energy of electrons emitted by a photocell is 2-8 V. What is the stopping potential ?

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To solve the problem, we need to determine the stopping potential (V_sp) given the maximum kinetic energy (KE_max) of the emitted electrons from a photocell. ### Step-by-Step Solution: 1. **Understanding the relationship between kinetic energy and stopping potential**: The maximum kinetic energy (KE_max) of the emitted electrons can be expressed in terms of the stopping potential (V_sp) using the formula: \[ KE_{max} = -e \cdot V_{sp} ...
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MBD -HARYANA BOARD-DUAL NATURE OF MATTER AND RADIATIONS-OBJECTIVE TYPE QUESTIONS
  1. The maximum kinetic energy of electrons emitted by a photocell is 2-8 ...

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  2. The wavelength of a wave with frequency 10^14 Hz will be :

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  3. If threshold wavelength for sodium is 6800Å then the work function wil...

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  4. For which of the following stopping potential required is maximum ?

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  5. The de-Broglie waves associated with an electron accelerated through a...

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  6. The wavelength of an electron of energy 10 keV will be :

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  7. If a proton and electron have the same de Broglie wavelength, then

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  8. The de-Broglie waves associated with an electron moving under a potent...

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  9. The rest mass of the photon is

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  10. When a proton is accelerated with 1 volt potential difference, then it...

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  11. Which of the following has the largest de Broglie wavelength (all have...

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  12. Plancks' constant has the dimensions of

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  13. Light of wavelength 4000 Å falls on a photosensitive plate with photoe...

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  14. The energy of a photon of wavelength lamda is given by

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  15. Stopping potential for which will be minimum ?

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  16. de-Broglie wavelength associated with an electron at V potential diffe...

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  17. Which of the following has minimum stopping potential?

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  18. The de-Broglie wavelength associated with a particle of momentum p is ...

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