The de Broglie wavelength associated with a ball of mass 150 g travelling at 30 m `s^(-1)` is

Explanation

The de-Broglie wavelength `lambda` is given by
`lambda = h/(mv)`
`=(6.62 xx 10^(-34))/(0.2 xx 30) = (6.62 xx 10^(-34))/4.5`
`=1.47 xx 10^(-34)`m.