State de-Broglie relation for wavelength of matter waves. Show that the de-Broglie wavelength of electrons accelerated through a potential of V volt can be expressed as :
`lambda = h/sqrt(2meV)`

Explanation

### Step-by-Step Solution:

**Step 1: State the de-Broglie relation.**
The de-Broglie relation states that the wavelength (\( \lambda \)) of matter waves is given by:
\[ \lambda = \frac{h}{p} \]
where \( h \) is Planck's constant and \( p \) is the momentum of the particle.
...