What conclusion do you draw when a radiation of frequency `10^(16)Hz` fails to produce photoelectrons from a metal surface?

Explanation

To analyze the situation where radiation of frequency \(10^{16} \text{ Hz}\) fails to produce photoelectrons from a metal surface, we can follow these steps:

### Step 1: Understand the Photoelectric Effect
The photoelectric effect occurs when light (or radiation) strikes a metal surface and causes the emission of electrons (photoelectrons). For this effect to happen, the energy of the incoming photons must be sufficient to overcome the work function (the minimum energy needed to remove an electron from the surface of the metal).

### Step 2: Relate Frequency to Energy
The energy of a photon can be calculated using the formula:
\[
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