Composition of a sample of Wustite is `Fe_(0-93)O_(1-0)`. What percentage of iron is present in the form of Fe (III)?

Explanation

`Fe_(0.93) O_(1-0)` is non-stoichiometric is a mixture of `Fe^(2+)` and `Fe^(3+)` ions. Let atoms of `Fe^(3+)` ions are present in the compound. This means that x `Fe^(3+)` ions have been replaced by `Fe^(2+)` ions.
No. of `Fe^(2+)` ions = 0.93 - x
For electrical neutrality,
Positive charge on the compound = Negative charge on the compound
2 (0.93 - x) + 3x = 2
1.86 + x = 2
x = 0.14
age of `Fe^(3+)` ions = `(0.14)/(0.93) xx 100`
= 15.05