सिद्ध कीजिएः `int "cosec"^(3) x dx=-1/2("cosec x cot x "+log |"cosec "x+cot x|)+c`

Similar Questions

Explore conceptually related problems

csc x=1+cot x

log("cosec x"-cot x)

int cosec^2 x dx=- cot x

Find int "cosec"x ( "cosec" x + cot x ) dx

int " cosec"^(m) x cot x dx =

itn "cosec" x log ("cosec" x-cot x)dx=

" cosec 2x + cot 2x = cot x "

int (dx)/(cosec 4x-cot 4x)

int cot^3x cosec^2 xdx