`sin(sin ^-1+cos^-1x)`=

Find the value of the following expression: sin(sin^(-1)x+cos^(-1)x),|x|,le1

The period of the function f(x)=sin(sin^(-1)x+cos^(-1)x-x) is

The value of x satisfying the equation (sin^(-1)x)^(3)-(cos^(-1)x)^(3)+(sin^(-1)x)(cos^(-1)x)(sin^(-1)x-cos^(-1)x)=(pi^(3))/(16) is :

sin (sin ^ (- 1) + cos ^ (- 1) x) =

Find the value of : sin (sin^(-1) x + cos^(-1) x)

If sin(sin^(-1)1/5+cos^(-1)x) =1 then x is equal to

Solve : (i)" "tan^(-1). x/2 +tan^(-1). x/3 = pi/4 , sqrt(6) gt x gt 0 (ii)" "sin(sin^(-1) . 1/5+cos^(-1)x)=1

sin^-1(-x) = -sin^-1(x); cos^-1(-x) = pi - cos^-1(x); tan^-1(-x) = -tan^-1(x); cot^-1(-x) = pi - cot^-1(x); sec^-1(-x) = pi - sec^-1(x); cosec^-1(-x) = -cosec^-1(X)

If y=(sin^(-1)x-cos^(-1)x)/(sin^(-1)x+cos^(-1)x)," then "(dy)/(dx)=