The mirror image of the circle "`x^(2)+y^(2)-10x-10y=0`" in the line "`x+y+5=0`" is a circle passing through the point:

Find the image of the circle x^(2)+y^(2)-2x+4y-4=0 in the line 2x-3y+5=0

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

Equation of the circle touching the circle x^(2) + y^(2) - 15x + 5y = 0 at the point (1, 2) and passing through the point (0, 2) is

The distance from the centre of the circle x^(2)+y^(2)=2x to the straight line passing through the points of intersection of the two circles x^(2)+y^(2)+5x-8y+1=0,x^(2)+y^(2)-3x+7y-25=0 is

A circle passing through the intersection of the circles x ^(2) + y^(2) + 5x + 4=0 and x ^(2) + y ^(2) + 5y -4 =0 also passes through the origin. The centre of the circle is

Center of a circle S passing through the intersection points of circles x^2+y^2-6x=0 &x^2+y^2-4y=0 lies on the line 2x-3y+12=0 then circle S passes through

y=2x is a chord of the circle x^(2)+y^(2)-10x=0, then the equation of a circle with this chord as diameter is

Find the equation of the circle concentric With the circle x^(2) + y^(2) - 4x - 6y - 9 = 0 and passing through the point ( -4, -5).