The distance travelled by a motor car in `t` seconds after the brakes are applied is `s` feet where `s=22t-12t^(2)`. The distance travelled by the car before it stops, is

The distance travelled by a motor car in t seconds after the brakes are applied is s feet where s = 22t -12t^(2) . The distance travelled by the car before it stop is

The distance travelled by a motor car in t second after the brakes are applied is s feet, where s = 22t -12t^(2) . The distance travelled by the car before it stops, is

The distance travelled by a motor car in t second after the brakes are applied is a feet, where s = 22t -12t^(2) .

The distance x metres travelled by a vehicle in time t seconds after the breakes are applied is given by x=20 t-(5)/(3) t^(2) . Determine (i) the speed of the vehicle (in km /hr) at the instant the brakes are applied and (ii) the distance the car travelled before it stops.

A car travels with a uniform velocity of 25 m s^(-1) for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find : (i) the distance which the car travels before the brakes are applied, (ii) the retardation,and (iii) the distance travelled by the car after applying the brakes.

A car is moving with constant speed 15 m//s . Suddenly the driver sees an obstruction on the road and takes 0.40 s to apply the brake, the brake causes a deceleration of 5 m//s^(2) . Find the distance traveled by the car before it stops.

If S=(1)/(3)t^(3)-4t^(2)+12t , then distance travelled by the particle before it first comes to rest is

If S=2t^(3)-4t^(2)+12t , then distance travelled during the time -interval [0,1] is