Find the equations of the sides of a triangle having (4, -1) as a vertex, if the lines `x-1=0` and `x -y-1=0` are the equations of two internal bisectors of its angles.

Find the equation of the sides of a triangle having B (-4, -5) as a vertex, 5x+3y-4=0 and 3x+8y+13=0 as the equations of two of its altitudes.

Find the equation of the sides of a triangle ABC with A(1,3) as a vertex and x-2y+1=0 and y-1=0 as the equation of two of its medians.

Find the equations of the sides of the triangle having (3, - 1) as a vertex, x - 4y + 10 = 0 and 6x + 10y - 59 = 0 being the equations of an angle bisector and a median respectively drawn from different vertices.

Find the equations of the sides of the triangle having (3, - 1) as a vertex, x - 4y + 10 = 0 and 6x + 10y - 59 = 0 being the equations of an angle bisector and a median respectively drawn from different vertices.

Two sides of a rhombus ABCD are parallel to the lines y = x + 2 and y = 7x + 3. If the diagonals of the rhombus intersect at the point (1, 2) and the vertex A is on the y-axis, find the possible coordinates of A. x – y – 1 = 0 are the equations of two internal bisectors of its angles.

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

In a triangle ABC , if the equation of sides AB,BC and CA are 2x- y + 4 = 0 , x - 2y - 1 = 0 and x + 3y - 3 = 0 respectively , The equation of external bisector of angle B is

The equation of the base of an equilateral triangle is x+y=2 and its vertex is (2,-1). Find the length and equations of its sides.

The equations of the sides of a triangle are x+y-5=0, x-y+1=0, and y-1=0. Then the coordinates of the circumcenter are

The equations of the sides of a triangle are x+y-5=0, x-y+1=0, and y-1=0. Then the coordinates of the circumcenter are