The `pH` of `LHE` in the following cell is `:`
`Pt, H_(2)(1atm)|H^(o+)(x M)||H^(o+)(0.1M)|H_(2)(0.1atm)Pt` E_(cell)=0.295V`.

pH of the anodic solution of the following cell is Pt, H_2(1atm)|H^+(xM)||H^(+)(1M)|H_2(1 atm ),Pt if E_("cell") =0.2364V.

pH of the anodic solution of the following cell is Pt, H_2(1atm)|H^+(xM)||H^(+)(1M)|H_2(1 atm ),Pt if E_("cell") =0.2364V.

The emf of the following cell is observed to be 0.118V at 25^(@)C . [Pt,H_(2)(1atm)|HA(100mL 0.1M||H^(o+)(0.1M)|H_(2)(1atm)|Pt] a. If 30mL of 0.2M NaOH is added to the negative terminal of battery, find the emf of the cell. b. If 50mL of 0.2 M NaOH is added to the negative terminal of battery, find the emf of teh cell.

The emf of the following cell is observed to be 0.118V at 25^(@)C . [Pt,H_(2)(1atm)|HA(100mL 0.1M||H^(o+)(0.1M)|H_(2)(1atm)|Pt] a. If 30mL of 0.2M NaOH is added to the negative terminal of battery, find the emf of the cell. b. If 50mL of 0.2 M NaOH is added to the negative terminal of battery, find the emf of teh cell.

For the cell Pt_((s)), H_(2) (1 atm)|H^(+) (pH=2)||H^(+) (pH=3)|H_(2) (1atm),Pt The cell reaction is

For the cell Pt_((s)), H_(2) (1 atm)|H^(+) (pH=2)||H^(+) (pH=3)|H_(2) (1atm),Pt The cell reaction is

E_("cell") of the following is Pt(s)|H_(2)(g), 1 "bar" |H^(+)(1M)||H^(+) (0.1 M)| H_(2)(g), I " bar" |Pt(s)

What is the emf of the following cell Pt:H_(2)(1"atm")|H^(+)(0.1M)||Cl_(2)(1"atm")|Cl^(-)(0.01M) at 298K(E_(Cl_(2))^(@)|Cl^(-)=1.36V)D