In Figure, `P Q=P Rdot` Show that `P S > P Q`

In figure, P Q=P R . Show that P S > P Q .

In Figure, P S=P R ,\ \ /_T P S=\ /_Q P Rdot Prove that P T=P Q

In Figure, If P Q=P T\ a n d\ /_T P S=/_Q P R , prove that \ P R S is isosceles

In Figure, A P _|_l a n d P R > P Q . Show that A R > A Q Given: A P_|_l a n d P R > P Q To Prove: A R > A Q Construction: Mark a point S on P R such that P S=P Qdot Join A S

In Figure, /_P Q R=\ /_P R Q , then prove that /_P Q S=\ /_P R Tdot

In Figure, P S=Q R\ a n d\ /_S P Q=/_R Q Pdot Prove that P Q S\ ~=\ Q P R ,\ P R=Q S\ a n d\ /_Q P R=\ /_P Q S

In Figure, P Q R S and A B R S are parallelograms and X is any point on side B Rdot Show that : a r(^(gm)P Q R S)=a r(^(gm)A B R S) a r(A X S)=1/2a r( P Q R S)

In Figure, P Q R is a triangle and S is any point in its interior, show that SQ+SR < PQ+PR. Given : S is any point in the interior of P Q R To Prove : S Q+S R < P Q+P R Construction: Produce Q S to meet P R in T

In Figure, A P\ _|_l\ a n d\ P R > P Q . Show that A R > A Q .

In Figure, P Q R is a triangle and S is any point in its interior, show that S Q+S R