`d^n/dx^n(1/(a x+b))`

If u=a x+b ,t h e n(d^n)/(dx^n)(f(a x+b)) is equal to a. (d^n)/(d u^n)(f(u)) b. a(d^n)/(d u^n)(f(u)) c. a^n(d^n)/(d u^n) f(u) d. a^(-n)(d^n)/(dx^n)(f(u))

If u=ax+b, then (d^(n))/(dx^(n))(f(ax+b)) is equal to a.(d^(n))/(du^(n))(f(u)) b.a(d^(n))/(du^(n))(f(u)) c.a^(n)(d^(n))/(du^(n))f(u) d.a^(-n)(d^(n))/(dx^(n))(f(u))

(d^n)/(dx^n)(logx)= ((n-1)!)/(x^n) (b) (n !)/(x^n) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)=? (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)= (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^n)/(dx^n)(logx)=? (a) ((n-1)!)/(x^n) (b) (n !)/(x^n) (c) ((n-2)!)/(x^n) (d) (-1)^(n-1)((n-1)!)/(x^n)

(d^(n))/(dx^(n))(log x)=(a)((n-1)!)/(x^(n))(b)(n!)/(x^(n))(c)((n-2)!)/(x^(n))(d)(-1)^(n-1)((n-1)!)/(x^(n))

(d)/(dx) {x ^(n) + (1)/(x ^(n))}=

Show that (d^n)/(dx^(n) )(x^(n) log x) = n! (log x + 1+(1)/(2) +…+(1)/(n)) AA n in N .

If y=a x^(n+1)+b x^(-n) , then x^2(d^2y)/(dx^2)= n(n-1)y (b) n(n+1)y (c) n y (d) n^2y