If `1/(1^2)+1/(2^2)+1/(3^2)+ tooo=(pi^2)/6,t h e n1/(1^2)+1/(3^2)+1/(5^2)+` equals `pi^2//8` b. `pi^2//12` c. `pi^2//3` d. `pi^2//2`

If 1/(1^2)+1/(2^2)+1/(3^2)+ .......=(pi^2)/6,t h e n1/(1^2)+1/(3^2)+1/(5^2)+.... equals a. pi^2//8 b. pi^2//12 c. pi^2//3 d. pi^2//2

If (1)/(1^(2))+(1)/(2^(2))+(1)/(3^(2))+...*to oo=(pi^(2))/(6), then (1)/(1^(2))+(1)/(3^(2))+(1)/(5^(2))+... equals pi^(2)/8 b.pi^(2)/12 c.pi^(2)/3 d.pi^(2)/2

If (1)/(1^(2))+(2)/(2^(2))+(3)/(3^(2))+...oo=(pi^(2))/(6) implies (1)/(1^(2))+(1)/(3^(2))+(1)/(5^(2))+...oo=(pi^(2))/(k) then k=

int_1^sqrt(3) (d x)/(1+x^2) equals a) pi/3 b) (2 pi)/3 c) pi/6 d) pi/(12)

The sum of the series tan ^(-1)"" (1)/( 1 + 1 + 1 ^(2)) + tan ^(-1)"" (1)/( 1 + 2 + 2 ^(2)) + tan ^(-1) ""(1)/( 1 + 3 + 3 ^(2)) +... is equal to : a) pi/4 b) pi/2 c) pi/3 d) pi/6

sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)

int_0^(pi//2)1/(1+cot^3x)dx is equal to 0 b. 1 c. pi//2 d. pi//4

int_0^(pi//2)1/(1+cot^3x)dx is equal to a 0 b. 1 c. pi//2 d. pi//4

The value of tan^(-1)(1)+cos^(-1)(-1/2)+sin^(-1)(-1/2) is equal to pi/4 b. (5pi)/(12) c. (3pi)/4 d. (13pi)/(12)

If sin^(-1)x+cos^(-1)(1)/(3)=(pi)/(2) ,then x is equal to: A) (1)/(3) B) (1)/(2) C) (pi)/(3) D) (pi)/(2)