यदि `|x| lt 1` तो सिद्ध कीजिए की
`(1-x)^(-3)=1+3x+6x^(2)+10x^(3)+...oo` पदों तक

1+3x+6x^(2)+10x^(3)+.oo, where (x=(1)/(3)) is

If x lt 1 , then 1/(x + 1) + (2x)/(1 +x^2) + (4x^3)/(1 + x^4) + ….oo =

Lt_(x rarr oo)(1)/((x-3)^(2))

lim_ (x rarr oo) (x ^ (3) + 6x ^ (2) +1) / (x ^ (4) +3)

यदि (x-1)^(3) (x+1) lt 0 तब x in

If f (x) = x-x ^(2) + x ^(3) - x ^(4) +….oo, |x| lt 1, then f '(x)=

1*2+2*3x+3*4x^(2)+.... oo (| x | <1)

Lt_(x to oo)(1-(7)/(x))^(3x)=

If (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) and x ne 1/3 then x=? यदि (3x-1)^3+(4x-3)^3+ (2x+1)^3= 3(3x - 1)(4x - 3)(2x +1) है तथा x ne 1/3 है, तो x=?