[" 14."(3x-1)/((x+2)^(2))],[" ultiply numerator and der "]

Let x="cos"(pi)/3+i "sin"(pi)/3 and Delta=|(1,x,x^(2)),(x^(2),1,x),(1,x^(2),1)| the numerical value of Delta is

If the k^(th) term in the expansion of (3/2 x^(2)- (1)/(3x))^(6) is independent of x , then the numerically greatest term in the expansion of (3/2 x^(2)- (1)/(3x))^(k) when x=2/3 , is

3x^(2)+14x+8

Sum to infinity 1^(2) + 2^(2) x+3^(2)x^(2)+4^(2)x^(3)+.... X lt 1 numerically .

The expression ((x-1)(x-2)(x^(2) - 9x + 14))/((x-7)(x^(2) - 3x + 2)) in the lowest terms is:

Solve : (3x +4)/(7) - (x +5)/(14) = (x)/(28) + (x +1)/(14) The following steps are involved in solving the above problem. Arrange them in sequential order (A) 5x + 3 = (3x + 2)/(2) rArr 10 x + 6 = 3x + 2 (B) rArr 7x = -4 (C) Given (3x + 4)/(7) - (x + 5)/(14) = (x)/(28) + (x +1)/(14) rArr (6x + 8 -x -5)/(14) = (x + 2x + 2)/(28) (D) rArr x = -(4)/(7)