`{:(3y + 2x = 0),(4y + 3x = 5):}`

{:(3x - 2y = 4),(5x - 2y = 0):}

The range of value of alpha such that (0,alpha) lies on or inside the triangle formed by the lines y + 3x + 2 = 0, 3y - 2x - 5 = 0, 4y + x - 14 =0 is

The line 3x + 2y = 6 will divide the quadrilateral formed y the lines x + y = 5, y – 2x = 8, 3y + 2x = 0 & 4y – x = 0 in

Solve: {:(3x - 4y - 1 = 0),(2x - (8)/(3)y + 5 = 0):}

2x + 3y = 0 , 3 x + 4y = 5 .

Solve for (x,y) : 2x-3y =5 , 3x+4y = -1 .

Simplify: (2x + 5y)(3x + 4y) - (7x + 3y)(2x + y)

Show that the three straight lines 2x-3y + 5 = 0 , 3x + 4y - 7 = 0 and 9x- 5y + 8 = 0 meet in a point

Show that the three straight lines 2x-3y + 5 = 0 , 3x + 4y - 7 = 0 and 9x- 5y + 8 = 0 meet in a point