Find `a` for which `lim_(n->oo) (1^a+2^a+3^a+...+n^a)/((n+1)^(a-1)[(na+1)+(na+2)+...+(na+n)])=1/60`

Find a for which lim_ (n rarr oo) (1 ^ (a) + 2 ^ (a) + 3 ^ (a) + ... + n ^ (a)) / ((n + 1) ^ (a- 1) [(na + 1) + (na + 2) + ... + (na + n)]) = (1) / (60)

For a epsilonR (the set of all real numbers) a!=-1, lim_(n to oo) ((1^(a)+2^(a)+………+n^(a)))/((n+1)^(a-1)[(na+1)+(na+2)+………..+(na+n)])=1/60 Then a=

For a epsilonR (the set of all real numbers) a!=-1 , lim_(n to oo) ((1^(a)+2^(a)+………+n^(a)))/((n+1)^(a-1)[(na+1)+(n+2)+………..+(na+n)])=1/60 Then a=

For a in R (the set of all real numbers),a!=-1)(lim)_(n rarr oo)((1^(a)+2^(a)++n^(a))/((n+1)^(a-1)[(na+1)+(na+2)+......(na+n)])=(1)/(60) Then a=(a)5 (b) 7(c)(-15)/(2) (d) (-17)/(2)

For a in RR (the set of all real numbers), a ne-1,underset(n to oo)lim(1^(a)+2^(a)+…+n^(a))/((n+1)^(a-1)[(na+1)+(na+2)+…+(na+n)])=(1)/(60) Then a =

lim_(n->oo)((n^2-n+1)/(n^2-n-1))^(n(n-1)) is

lim_(n->oo)((n^2-n+1)/(n^2-n-1))^(n(n-1)) is

lim_(n->oo)((n^2-n+1)/(n^2-n-1))^(n(n-1)) is