A particle moves along a line according to the law `s=4t^3-3t^2+2`. At what time will the acceleration be equal to 42 unit/`sec^2` ?

A particle moves along a line according to the law s=t^4-5t^2+8 . The intial velocity is

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then :-

A particle moving according to the law s=6t-1/2t^3 . At what time its velocity vanishes ?

A particle moves along a straight line according to the law s=t^3-3t^2+5t . Find its velocity and acceleration at the end of 1 sec.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the particle's acceleration each time the velocity is zero.

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . At what times the particle changes direction?

A particle is moving along a line according to the law s=t^3-3t^2+5 . The acceleration of the particle at the instant where the velocity is zero is

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle moves so that the distance moved is according to the law s(t)=t^3/3-t^2+3 . At what time the velocity and acceleration are zero respectively?

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then The average acceleration from 1 le t le 2 second is