`x^(log_5 x) > 5` implies `x in `

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x^((log)_5x)>5 implies x in (0,oo) (b) (0,1/5)U(5,∞) (c) (2,2.5) (d) (0,2.5)

x^((log)_5x)>5 implies x in (0,oo) (b) [2,2.5] (c) (2,2.5) (d) (0,2.5)

log_(0.5)log_5(x^2-4)gtlog_(0.5)1 , then 'x' lies in the interval

The number of values of x satisfying 2^(log_5 16. log_4 x +x log_2 5) + 5^x + x^((log_5 4)+5) + x^5 = 0