Home
Class 7
MATHS
If x + (1)/(x) = 6 , then find x^(2) + ...

If ` x + (1)/(x) = 6` , then find `x^(2) + (1)/(x^(2))` .

A

34

B

36

C

32

D

38

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we start with the equation given: **Step 1:** We are given that \( x + \frac{1}{x} = 6 \). **Step 2:** To find \( x^2 + \frac{1}{x^2} \), we will square both sides of the equation \( x + \frac{1}{x} = 6 \). \[ \left( x + \frac{1}{x} \right)^2 = 6^2 \] **Step 3:** Expanding the left side using the formula \( (a + b)^2 = a^2 + 2ab + b^2 \): \[ x^2 + 2 \cdot x \cdot \frac{1}{x} + \frac{1}{x^2} = 36 \] **Step 4:** Simplifying the equation: Since \( 2 \cdot x \cdot \frac{1}{x} = 2 \), we have: \[ x^2 + 2 + \frac{1}{x^2} = 36 \] **Step 5:** Rearranging the equation to isolate \( x^2 + \frac{1}{x^2} \): \[ x^2 + \frac{1}{x^2} = 36 - 2 \] **Step 6:** Performing the subtraction: \[ x^2 + \frac{1}{x^2} = 34 \] Thus, the final answer is: \[ \boxed{34} \] ---

To solve the problem, we start with the equation given: **Step 1:** We are given that \( x + \frac{1}{x} = 6 \). **Step 2:** To find \( x^2 + \frac{1}{x^2} \), we will square both sides of the equation \( x + \frac{1}{x} = 6 \). \[ \left( x + \frac{1}{x} \right)^2 = 6^2 ...
Promotional Banner

Similar Questions

Explore conceptually related problems

If 3x + (1)/(x) = 6 , then find 9x^(2) + (1)/(x^(2)) .

If (x - (1)/(x)) = 6 , then (x^(2) + (1)/(x^(2))) = ?

if x+(1)/(x)=5 then find x^(2)-(1)/(x^(2))

If x+(1)/(x)=3, then find x^(2)-(1)/(x^(2)),x^(2)+(1)/(x^(2))

If x+(1)/(x)=6, find x^(2)+(1)/(x^(2))

If x+(1)/(x)=6 find the value of x^(2)+(1)/(x^(2))=?

If x+(1)/(x)=6, find x^(2)+(1)/(x^(2))( ii) x^(4)+(1)/(x^(4))