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ABCD is a kite in which AB=AD and CB=CD....

ABCD is a kite in which AB=AD and CB=CD. If `angleABD=25^(@) and angleBDC=35^(@)`, then find `angleA-angleC`.

Text Solution

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Given `angleABD=25^(@) and anlgeBDC=35^(@)`.
In `DeltaBCD,BC=CD`.
`implies angleCDB=angleCBDimpliesangleCBD=35^(@)`
`implies angleC=180^(@)-(35^(@)+35^(@))=110^(@)`
AB=AD
Also given,
`implies angleABD=angleADBimpliesangleADB=25^(@)`
`angleA=180^(@)-(25^(@)+25^(@))=130^(@)`
Now,
`:. angleA-angleC=130^(@)-110^(@)=20^(@)`
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