[" the value of "k" so that the plane "(k+1)x-y+(2-k)z=5" is perpendicular to "],[" lane "2x+6y-z+3=0" ."]

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other is

The value of k for which the planes 3x-6y-2z=7 and 2x+y-kz=5 areperpendicular to each other is

Find the value of k for whicj the planes: 3x-6y-2z=7 and 2x+y-kz=5 are perpendicular to each other.

The value k for which the line (x-1)/(8)=(y+2)/(k)=(z-3)/(-6) is perpendicular to the plane 4x+2y-3z=5 is -

The value of k such that the line (x-4)/1=(y-2)/1=(z-k)/2 lies on the plane 2x - 4y + z = 7 is

Write the value of k for which the planes 2x-5y+kz=4 and x+2y-z=6 are perpendicular to each other.

If the planes 2x+3y-z+5=0, x+2y-kz+7=0 are perpendicular then k =

Find the value of k for which the line (x - 2)/3 = (1 - y)/k = (z - 1)/4 is parallel to the plane 2x + 6y + 3z - 4 = 0.

Find the value of 'k' for which the plane : 3x - 6y - 2z = 7 and 2x + y - kz = 3 are perpendicular to each other.