Position of a particle as a function of time is given as `x^2 = at^2 + 2bt + c`, where a, b, c are constants. Acceleration of particle varies with `x^(-n)` then value of n is.

The displacement x of a particle at time t moving along a straight line path is given by x^(2) = at^(2) + 2bt + c where a, b and c are constants. The acceleration of the particle varies as

The position of a particle as a function of time t, is given by x(t)=at+bt^(2)-ct^(3) where a,b and c are constants. When the particle attains zero acceleration, then its velocity will be :

The displacement of a particle after time is given by x = k/b^2 (1-e^(-bt)) where 'b' is a constant. The acceleration of the particle is

The displacement x of a particle in rectilinear motion at time t is represented as x^(2) = at^(2) +2bt+c , where a ,b, and c are constants. Show that the acceleration of this particle varies (1)/(x^(3)) .

The displacement of the particle along a straight line at time t is given by X=a+bt+ct^(2) where a, b, c are constants. The acceleration of the particle is

The displacement of a particle is s = (a+bt)^(6) , where a and b are constants. Find acceleration of the particle as a function of time.

For a body in a uniformly accelerated motion, the distance of the body from a reference point at time 't' is given by x = at + bt^2 + c , where a, b , c are constants. The dimensions of 'c' are the same as those of (A) x " " (B) at " " (C ) bt^2 " " (D) a^2//b